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The Specified Child Already Has A Parent In Android

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so try to remove dialog.show(). To emailaddress: To name: From name: Extra information in the email body (optional): Email: I am sending you the codedump of java.lang.IllegalStateException: The specified child already has a parent that you Of course, it would be better to save a reference to the LayoutInflater outside the loop, and use that instead. –Mike M. May be it could help..

current community chat Stack Overflow Meta Stack Overflow your communities Sign up or log in to customize your list. Passing the container is important in order for the system to apply layout parameters to the root view of the inflated layout, specified by the parent view in which it's going. more common way to say "act upon word or a promise" How do manufacturers detune engines? You must call removeView() on the child's parent first. 04-18 13:24:12.735: E/AndroidRuntime(6321): at android.app.ActivityThread.performLaunchActivity(ActivityThread.java:1728) 04-18 13:24:12.735: E/AndroidRuntime(6321): at android.app.ActivityThread.handleLaunchActivity(ActivityThread.java:1747) 04-18 13:24:12.735: E/AndroidRuntime(6321): at android.app.ActivityThread.access$1500(ActivityThread.java:155) 04-18 13:24:12.735: E/AndroidRuntime(6321): at android.app.ActivityThread$H.handleMessage(ActivityThread.java:993) 04-18 13:24:12.735: this website

The Specified Child Already Has A Parent In Android

You must call … on Android0Specified child already has parent0Getting “the specific child already has a parent.” Hot Network Questions Could you make me a hexagon please? Solve equation in determinant How do I dehumanize a humanoid alien? ViewPager class: @Override public Fragment getItem(int position) { // return SwipeyTabFragment.newInstance(TITLES[position]); Fragment f = new Fragment(); switch (position) { case 0: f = History.newInstance(position); break; case 1: f = Main.newInstance(position); break;

share|improve this answer answered Jan 16 '15 at 14:28 Pranav 1,0741118 add a comment| up vote 0 down vote // if the child view to be added is already bound to Your answer really was a life saver. :) –Noni A. You must call removeView() on the child's parent first5Issue: specified child already has a parent. Java.lang.unsupportedoperationexception: Removeview(view) Is Not Supported In Adapterview This was the original xml file: Now with the LinearLayout

Nov 11 '15 at 10:04 1 Right, right. Java.lang.illegalstateexception: The Specified Child Already Has A Parent Politely asking for more work as an intern What is this device attached to the seat-tube? Thanks a lot! –L93 Jan 10 '15 at 15:20 return parent still got the exception –Allen Vork Oct 10 at 9:50 add a comment| up vote 1 down vote http://stackoverflow.com/questions/13559353/how-to-solve-for-viewpager-the-specified-child-already-has-a-parent-you-must Browse other questions tagged android android-fragments android-listview android-listfragment or ask your own question.

If you are asking when you would want to attach an inflated View to a parent, then there are a few situations. Removeview Android Example more hot questions question feed default about us tour help blog chat data legal privacy policy work here advertising info mobile contact us feedback Technology Life / Arts Culture / Recreation You must call removeView() on the child's parent first. Solution: I just checked to see if the child view I was trying to display (instantiate) was already instantiated somewhere else by seeing if it had a parent view set.

Java.lang.illegalstateexception: The Specified Child Already Has A Parent

Code commented out: // Begin the transaction FragmentTransaction ft = getFragmentManager().beginTransaction(); // Replace the container with the new fragment ft.add(R.id.contacts_fragment, new ContactsFragment()); // Execute the changes specified ft.commit(); AddressBook.java package org.azurespot.practiceapp.addressbook; http://stackoverflow.com/questions/13470267/android-fragment-the-specified-child-already-has-a-parent-fragment-error Now the user clicks on the next tab, and the app shows the content. The Specified Child Already Has A Parent In Android Not the answer you're looking for? You Must Call Removeview() On The Child's Parent First Here is my code (I apologize if it offends any experts): @Override public Object instantiateItem(View container, int position) { LinearLayout v = new LinearLayout(mContext); //the view being loaded (unless it already

selected 2015-07-25 01:16:15 UTC #4 try this. ((CamActivity)getActivity()).finish(); 主页 分类 FAQ/指引 服务条款 隐私政策 采用 Discourse,启用 JavaScript 以获得最佳效果 CodeDump Add Browse Sign up Sign in Select language ActionScript Ajax Android AngularJS Apache as you have given the suggestion "remove the return statement should solve your problem" but we need to return View object in onCreateView() method. I hope this helps. You can solve it by just add single line mViewPager.setOffscreenPageLimit(3); public class SwipeyTabsSampleActivity extends FragmentActivity { ... @Override public void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); setContentView(R.layout.main); mViewPager = (ViewPager) findViewById(R.id.viewpager); mTabs = Add Multiple View To Linearlayout Programmatically

Is it possible to get a professor position without having had any fellowships in grad school? Look into R.layout.full_image and see that if R.id.framelayout is already enclosed in a parent ViewGroup. Thanks every one! Jul 12 '13 at 15:58 Updated with logcat –Papajohn000 Jul 12 '13 at 16:03 add a comment| 3 Answers 3 active oldest votes up vote 10 down vote accepted

RouteSearchFragment df = RouteSearchFragment.newInstance(index); // Execute a transaction, replacing any existing fragment // with this one inside the frame. Android Removeview What is so wrong with thinking of real numbers as infinite decimals? EDIT: Without intent into Map activity it works pwrfect.I mean when i am using same as history into map there is no any error.

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Whose murder is it? Arguments of \newcommand as variable names? What would be a good choice for a controlled opposition? Fragmentmanager Is Already Executing Transactions Add false as third argument..

getting the same error!! –Vivek Apr 18 '14 at 8:19 add a comment| Your Answer draft saved draft discarded Sign up or log in Sign up using Google Sign up more stack exchange communities company blog Stack Exchange Inbox Reputation and Badges sign up log in tour help Tour Start here for a quick overview of the site Help Center Detailed Shortest auto-destructive loop Arguments of \newcommand as variable names? Switch that line to the following, and you should be fine.

Does this help anyone know more about the nature of the error? So it does not reload, i do the following in the onCreateView of the Diagramm-Fragment: @Override public View onCreateView(LayoutInflater inflater, ViewGroup container, Bundle savedInstanceState) { if(layout == null){ layout = new Is this a scam? On capturePic click or before it. –maddy d Apr 18 '14 at 8:08 where should i call getParent?? @maddy before it –Vivek Apr 18 '14 at 8:10 1

You must call removeView() on the child's parent first 0 ViewPager error :The specified child already has a parent. The Problem: Let us assume the User clicks on the specific Tab, the computing of the diagramm starts and everything works fine. I was calling it twice 1.from where i called the dialog. 2.in the dialog.